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Prove an argument

Here is an intuitionistically valid argument. Give a proof of it in NJ. (You might want to work this out on scratch paper first!)

  • ((y ∨ p) ∧ l) ∧ ((y ∨ p) ∧ l)
  • ----------------
  • y ∨ p
How to enter a proof:
  • You can input connectives by using the symbols below or their ASCII approximations as shown:
    Connective Write (click to copy symbol to your clipboard):
    Negation
    Conjunction
    Disjunction
    Implication
    Falsum
  • For practice entering proofs, you can check out the proof playground
  • For rule labels, use the connective plus I for introductions or E for eliminations. For disjunction introductions and conjunction eliminations, you should add in addition an L or R as appropriate. For example, you might write ∧I or ∧EL.
  • For discharging rules (that's →I, ¬I, and ∨E), add a numeral to the end of the rule name as a discharge marker. For example, you might use →I5 or ∨E23.
  • To discharge an assumption, surround it with [ and ], and put the appropriate discharge numeral immediately after that. For example, you might write [p -> q]3 to discharge the assumption p -> q with the label 3.
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  • Finally, if you run into bugs or difficulties, please let me know! Screenshots are very much appreciated.